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`2mol` each of `A` and `B` are taken in a container to carry out the following reaction:
`2A(g)+B(g)hArr2C(g)+2D(g)`
When the system attains equilibrium, we have
A. `[A]lt[B]`
B. `[A]gt[B]`
C. `[A]=[B]`
D. `[A]=[B]=[C]=[D]`

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Correct Answer - A
According to the stoichiometry of the reaction, for `1 mol` of `B` consumed, `2 mol` of `A` are converted into products. Thus, at equilibrium, the concentration of `A` will be less than that of B as we start with equal concentrations of `A` and `B`.

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