Correct Answer - A
`C_(H^(+))=10^(-pH)mol L^(-1)`
Thus, pH = 5 means
`C_(H^(+))= 10^(-5)mol L^(-1)`
According to molarity equation, we have
`M_(i)V_(i)= M_(f)V_(f)`
`(10^(-5)mol L^(-1))(x)= M_(f)(100 x)`
`:. M_(f)=10^(-7)mol L^(-1)`
Under these conditions, the contribution of `H^(+)` from `H_(2)O` cannot be neglected. This will make the solutions slightly. acidic but practically neutral. In fact, its pH is `6.699~~7`.
