Question

9.2 grams of `N_(2)O_(4) (g)` is taken in a closed one litre vessel and heated till the following equilibrium is reached
` N_(2) O_(4) (g) hArr 2 NO_(2) (g) `
At equilibrium , 50% `N_(2)O_(4)` (g) is dissociated . What is the equilibrium constant ( in mol `lit^(-1)) (" Molecular weught of" N_(2)O_(4) = 92`)
A. `0.1`
B. `0.2`
C. `0.4`
D. 2

Answer 1

Correct Answer - B
Intial ` [N_(2)O_(4)] = 9.2//92 " mol"L^(-1) = 0.1 " mol "L^(-1)`
At. Eqm. ( after 50% dissociation ),
`[N_(2)O_(4)] = 0.05 M, [NO_(2)] = 0.1 M`
` K = ([NO_(2)])/([N_(2)O_(4)])=(0.1)^(2)/0.05 = 0.2`