Question

`K_(p) " for the reaction ,"N_(2) (g) + 3 H_(2) (g) hArr 2NH_(3) " is " 49` at a certain temperature. Calculate the value `K_(p)` at the same temperature for the reaction

Answer 1

Given : `N_(2) (g) + 3 H _(2) (g) hArr2 NH_(3)(g) , K_(p) = 49`
` " For the reverse reaction, " 2 N H_(3) (g) hArr N_(2)(g) + 3 H_(2) (g) , H_(p) = 1/49`
` " On dividing by 2, we have " NH_(3) (g) hArr 1/2 N_(2) (g) + 3/2 H_(2) (g) , K _(p) = sqrt(1/49) = 1/7.`