Question

For an isothermal reversible expansion process, the value of q can be calculated by the expressin
A. `q=2.30 n RT log. (V_(2))/(V_(1))`
B. `q=-2.303nRT log.(V_(2))/(V_(1))`
C. `q=-2.303 nRT log. (V_(1))/(V_(2))`
D. `q=-P_("exp")nRT log.(V_(1))/(V_(2))`

Answer 1

Correct Answer - A
`q=-W=2.303nRT log(V_(2))/(V_(1))`