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Draw graphs of x- 2y = 4, 2x – 4y = 12 on the same co-ordinate plane. Observe it. Think of the relation between the coefficients of x, coefficients of y and the constant terms and draw the inference.

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i. x - 2y = 4

∴ 2y = x - 4

∴ y = (x - 4)/2

x 0 2 -2 4
y -2 -1 -3 0
(x, y) (0, -2) (2, -1) (-2, -3) (4, 0)

2x - 4y = 12

∴ x -2y = 6

∴ 2y = x - 6

∴ y = (x - 6)/2

x 0 -2 2 4
y -3 -4 -2 -1
(x, y) (0, -3) (-2, -4) (2, -2) (4, -1)

ii. Ratio of coefficients of x = 1/2

Ratio of coefficients of y \(=\frac{-2}{-4} = \frac{1}{2}\)

Ratio of constant terms \(=\frac{4}{12} = \frac{1}{3}\)

∴ Ratio of coefficients of x = ratio of coefficients of y ratio of constant terms

iii. If ratio of coefficients of x = ratio of coefficients of y ≠ ratio of constant terms, then the graphs of the two equations will be parallel to each other.

Condition of consistency in Equations:

Sr. No. Simultaneous Equations \(\frac{a_1}{a_2}\) \(\frac{b_1}{b_2}\) \(\frac{c_1}{c_2}\) Comparison of ratios Graphical Interpretation Algebraic Interpretation
1. x + y = 3; x - y = 1 \(\frac{1}{1}\) \(\frac{1}{-1}\) \(\frac{3}{1}\) \(\frac{a_1}{a_2} \neq \frac{b_1}{b_2}\) Intersecting lines Unique solution (OR) Only one common solution
2. 2x - y = -1; 2x - y = 4 \(\frac{2}{2}\) \(\frac{-1}{-1}\) \(\frac{-1}{4}\) \(\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}\) Parallel lines No solution
3. x - y = -2; 2x - 2y = -4 \(\frac{1}{2}\) \(\frac{-1}{-2}\) \(\frac{-2}{-4}\) \(\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}\) Coincident lines Infinity many solutions

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