The radical halogenation of 2-methylpropane gives two products: `(CH_(3))_(2)CHCH_(2)X` (minor) and `(CH_(3))_(3)CX` (major) Chlorination gives a larger amount of the minor product than does bromination, why?
A. Bromine is more reactive than chlorine and is able to attack the less reactive `3^(@)C-H`
B. Bromine atoms are less reactive (more selective) than chlorine, and preferentially attack the weaker `3^(@)C-H` bond
C. The methyl groups are more hindered to attack by the larger bromine atom.
D. Bromination is reversible and more stable `3^(@)-` alkyl bromide is formed exlusively.
