27 g of Al (at mass=27) will react completely with oxygen equal to

a) The equation of the reaction of aluminium and oxygen, is as
`4Al + 3O_(2) to 2Al_(2)O_(3)`
therefore 108 g of AI reacts with 96g of `O_(2)`.
therefore 27g of AI with react with `=(96 xx 27)/(108)` = 24 g of `CO_(2)`

27 g of Al (at mass=27) will react completely with oxygen equal to

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