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27 g of Al (at. Mass 27) will react completely with oxygen equal to

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27 g of Al (at. Mass 27) will react completely with oxygen equal to
A. `24g`
B. `8g`
C. `40g`
D. `10g`
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1 Answer

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Best answer
Correct Answer - A
`underset(4xx27g)(4Al)+underset(3xx32g)(3O_(2))to2Al_(2)O_(3)`
27 g of Al will react with oxygen
`=(3)/(4)xx32=24g`
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