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An aqueous solution freezes at
`-0.186^(@)C (K_(f)=1.86^(@)` ,`K_(b)=0.512^(@)`. What is the elevation in boiling point?
A. 0.186
B. 0.512
C. `(0.512)/(1.86)`
D. 0.0512

1 Answer

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Best answer
Correct Answer - D
`DeltaT=K_(f)xxm`
`0.186=1.86xxm`
`m=0.1`
`DeltaT=K_(b)xxm=0.512xx0.1 =0.0512`]

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