Question

An aqueous solution freezes at
`-0.186^(@)C (K_(f)=1.86^(@)` ,`K_(b)=0.512^(@)`. What is the elevation in boiling point?
A. 0.186
B. 0.512
C. `0.512/1.86`
D. 0.0512

Answer 1

Correct Answer - D
`DeltaT_(b) = K_(b) xx Molality`
`DeltaT_(f) = K_(f) xx Molality`
`:. (DeltaT_(b))/(DeltaT_(f))=K_(b)/K_(f) rArr (DeltaT_(b)) =(DeltaT_(f) xx DeltaT_(b))/DeltaT_(f) =(0.186 xx 0.512)/1.86`
`=0.0512`