Question

50 g of copper is heated to increase its temperature by `10^@C`. If the same quantity of heat is given to `10g` of water, the rise in its temperature is (specific heat of copper`=420J//kg^(@)//C`)
A. `5^@C`
B. `6^@C`
C. `7^@C`
D. `8^@C`

Answer 1

Correct Answer - A
Same amount of heat is supplied to copper and water, so
`m_(c)c_(c)DeltaT_c=m_omegac_omegaDeltaT_omega`
`implies(DeltaT)_omega=(m_(c)c_cDeltaT_c)/(m_omegac_omega)=(50xx10^-3xx420xx10)/(10xx10^-3xx4200)=5^@C`