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A uniform steel rod of cross- sectional area `A` and `L` is suspended so that it hangs vertically. The stress at the middle point of the rod is
A. `(L)/(2A)rhog`
B. `(Lrhog)/(2)`
C. `(LA)/(rhog)`
D. `Lrhog`

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Correct Answer - B
(c) At middle , T=weight of half the length of steel bar
`=((L)/(2))Arhog`
`therefore` Stress `=(T)/(A)=(Lrhog)/(2)`

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