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A particle undergoes `SHM` along a straight line and its velocities while passing though points `3cm` and `4cm` form the mean position are `16 cm//s` and `12 cm//s` respectively. Its time period is
A. `(pi)/(2)s`
B. `pis`
C. `(3pi)/(2)s`
D. `2pis`

1 Answer

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Best answer
Correct Answer - A
`T = 2pi sqrt((y_(2)^(2)-y_(1)^(2))/(v_(1)^(2)-v_(2)^(2)))`

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