Question

The friction of the air causes a vertical retardation equal to `10%` of the acceleration due to gravity. Take `g=10 m//s^(2)` the maximum height and time to reach the maximum height will be decreased by
A. `9%,9%`
B. `11%,11%`
C. `9%,10%`
D. `11%,9%`

Answer 1

Correct Answer - A
`hprop(1)/(g),(h_(2))/(h_(1))=(g_(1))/(g_(2)),(h_(2)-h_(1))/(h_(1))xx100=(g_(1)-g_(2))/(g_(2))xx100`
`g_(1)=g+(g)/(10)=(11g)/(10)`