Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
6.6k views
in Physics by (86.0k points)
closed by
An astronomical telescope of magnifying power `7` consists of two thin lenses `40 cm` apart, in normal adjustment. Calculate the focal lengths of the lenses.

1 Answer

+1 vote
by (86.6k points)
selected by
 
Best answer
Here, `M = (f_0)/(f_e) = 7` or `f_0 = 7 f_e`
In normal adjustment, distance between the lenses, `f_0 + f_e = 40 cm`
:. `7 f_e + f_e = 40, f_e = (40)/(8) = 5 cm`
`f_0 = 7 f_e = 7 xx 5 = 35 cm`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...