# From the top of a tower a stone is thrown up which reaches the ground in time t_(1). A second stone thrown down with the same speed reaches the grou

29 views
in Physics
closed
From the top of a tower a stone is thrown up which reaches the ground in time t_(1). A second stone thrown down with the same speed reaches the ground in a time t_(2). A third stone released from rest from the same location reaches the ground in a time t_(3). then:
A. (1)/(t_(3)) = (1)/(t_(1)) + (1)/(t_(2))
B. t_(3)^(2) = t_(1)^(2) - t_(2)^(2)
C. t_(3) = (t_(1) + t_(2))/(2)
D. t_(3) = sqrt(t_(1) t_(2))

by (76.5k points)
selected

-H = ut_(1) - (1)/(2) g t_(1)^(2)
H = u t_(2) + (1)/(2) g t_(2)^(2)
H = (1)/(2) g t_(3)^(2)