Question

The range of a projectile fired at an angle of `15^@` is 50 m. If it is fired with the same speed at an angle of `45^@` its range will be
A. `60 m`
B. `71 m`
C. `100 m`
D. `141 m`

Answer 1

Correct Answer - C
`R=50m=(u^(2)sin(2xx15^(@)))/g`
`u=31.304m//s`
`theta=45^(@),R=(u^(2)sin(2xx15^(@)))/g=100m`