Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
81 views
in Physics by (41.5k points)
closed by
The range of a projectile fired at an angle of `15^@` is 50 m. If it is fired with the same speed at an angle of `45^@` its range will be
A. 60 m
B. 71 m
C. 100 m
D. 141 m

1 Answer

0 votes
by (57.3k points)
selected by
 
Best answer
Correct Answer - C
Horizontal range, `R = (u^(2) sin 2theta)/(g)`
For the same speed.
`R prop sin 2theta`
`therefore (R_(1))/(R_(2)) = (sin2 xx15^(@))/(sin2 xx 45^(@)) = (sin 30^(@))/(sin 90^(@))`
or `R_(2) = R_(1) (sin 90^(@))/(sin 30^(@)) = 50 m xx(1)/(((1)/(2))) = 100m`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...