Question

Two tuning forks with natural frequencies of `340 Hz` each move relative to a stationary observer. One fork moves away form the observer, while the other moves towards him at the same speed. The observer hears beats of frequency `3 Hz`. Find the speed of the tuning fork.

Answer 1

Correct Answer - `1.5 m//s`
`Delta f=f_(0)((v)/(v-v_(S)))-f_(0)((v)/(v+v_(S)))=3`
`rArr 3=340[(330)/(330-V_(S))-(330)/(330+V_(S))]rArr V_(S)=1.5m//s`