Question

One cm on the main scale of vernier callipers is divided into ten equal parts. If 0 divisions of vernier so coincide with 8 small divisions of the main scale. What will be the least count of callipers ?

Answer 1

20 division of vemier scale = 8 division of main scale `rArr ` 1 VSD = `((8)/(20))` MSD = 0.4 MSD
Least count = 1 MSD - 1 VSD = 1 MSD - 0.4 MSD = 0.6 MSD
`= 0.6xx0.1 cm = 0.06 cm ( because ` 1MSD =`(1)/(10)` cm = 0.1 cm)