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One centimetre on the main scale of vernier callipers is divided into ten equal parts. If 10 divisions of vernier scale coincide with 8 small divisions of the main scale, the least count of the callipers is
A. 0.01 cm
B. 0.02 cm
C. 0.05 cm
D. 0.005 cm

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Best answer
Correct Answer - B
L.C = `((b-a)/(b))M= ((10-8)/(10))xx (1)/(10)` cm = 0.02 cm

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