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Two masses `m_(1)` and `m_(2)` are accelerated uniformly on a frictionless surface as shown in figure given below. The ratio of the tensions `T_(1)/T_(2)` is:
image
A. `m_(1)/m_(2)`
B. `m_(2)/m_(1)`
C. `((m_(1)+m_(2)))/m_(2)`
D. `m_(1)/((m_(1)+m_(2)))`

1 Answer

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Best answer
Correct Answer - D
`T_(1)=m_(1)a and T_(2)=(m_(1)+m_(2))a`
`:.(T_(1))/T_(2)=m_(1)/((m_(1)+m_(2)))`

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