Question

The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at `0^(@)C` is
A. 10.52 cal/(mol K)
B. 21.04 cal/(mol K)
C. 5.260 cal/(mol K)
D. 0.526 cal/(mol K)

Answer 1

Correct Answer - C
`DeltaS=(DeltaH)/(T)=(1.435xx10^(3))/(273)=5.260 cal//"molK"`