Question

The enthalpy of fusion of water is `1.435 kcal//"mole"`. The molar entropy change for melting of ice at `0^(@)C` is
A. `10.52 cal//(mol K)`
B. `21.04 cal//(mol K)`
C. `5.260 cal//(mol K)`
D. `0.526 cal//(mol K)`

Answer 1

Correct Answer - C
`Delta_(f)H^(@) =1.435 kcal//mol=1435 cal//mol`
`DeltaS=Delta_(f)^(@)H=(1435)/(273)=5.256 cal K^(-1)mol^(-1)`