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0.16 gm of a dibasic acid require 25 ml of decinormal NaOH solution for complete neutralization. The moleucular weight of the acid
A. 32
B. 64
C. 128
D. 256

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Correct Answer - C
`(0.16)/(x)xx(1000)/(25)=(1)/(10)implies(6.4)/(x)=(1)/(10) thereforex=64`
Mol. Wt.=`64xx2=128`.

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