Correct Answer - C
`sec 11^(@).sec 19^(@)-2 cot 71^(@)`
`=(1)/(cos 11^(@)cos 19^(@))-(2 sin 19^(@))/(cos 19^(@))`
`=(1-2 sin 19^(@)cos 11^(@))/(cos 11^(@)cos 19^(@))`
`=(1-(sin 30^(@)+sin 8^(@)))/(cos 11^(@)cos 19^(@))`
`=(1-(1//2)-sin 8^(@))/(cos 11^(@)cos 19^(@))`
`=(sin 30^(@)-sin 8^(@))/(cos 11^(@)cos 19^(@))`
`=(2 sin 11^(@).cos 19^(@))/(cos 11^(@)cos 19^(@))`
`2 tan 11^(@)`