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यदि `A=tan11^(@)tan29^(@),B=2cot61^(@)cot79^(@)` है तो
A. A=2B
B. `A=-2B`
C. `2A=B`
D. `2A=-B`

1 Answer

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Best answer
Correct Answer - c
`(A)/(B)=(tan 11^(@)tan29^(@))/(2cot61^(@)cot79^(@))`
`(A)/(B)=(tan 11^(@)tan29^(@))/(2(cot(90^(@)-29^(@))cot(90^(@)-11^(@)))`
`(A)/(B)=(tan11^(@)tan29^(@))/(2tan11 ^ (@)tan29^(@))`
`(A)/(B)=(1)/(2)`
2A=B

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