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In a cold climate water gets frozen causing damage to radiator of a car. Ethylene glycol is used as an anifreezing agent. Calculate the amount of ethylene glycol to be added to `4 kg` of water to prevent it from freezing at `-6^(@)` . (`K_(f)` for water = `1.85 kg mol^(-1)`)

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Given,
`DeltaT =6^(@)C`,`W_(2)=4 kg = 4000g`,`Mw_(2)=62`,`K_(f)=1.85`
`W_(2) =(Mw_(2)xxW_(1)xxDeltaT)/(1000xxK_(f))`
`(62xx4000xx6)/(1000xx1.85) =804.32 g`.

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