Question

A body of volume loo cm³ is immersed completely in water. Find the weight of the water displaced by the body. 1g = 9.8 m/s² . p (water) = kg/m³ ]

Answer 1

Data: V = 100 cm³ = 100 × 10^-6 m³

= 1 × 10 m³, p(water) = 10 kg/m³

g = 9.8 m/s², weight of the displaced water ?

Density = \(\cfrac{mass}{volume}\)

∴ Mass = volume × density 

Volume of the water displaced by the body = l × 10^-4 m³

∴Mass of the water displaced,

m = l × 10^-4 m³ x 10 kg/m³ = 0.1 kg

∴Weight of the water displaced

= mg = 0.1 kg × 9.8 m/s² = 0.98 N.

The weight of the water displaced by the body = 0.98 N.