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A coil resistance `20 W` and inductance `5 H` is connected with a `100 V` battery. Energy stored in the coil will be
A. `41.5J`
B. `62.50 J`
C. `125J`
D. `250J`

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Best answer
Correct Answer - B
`U=(1)/(2)Li^(2)=(1)/(2)L((E)/(R ))^(2)=(1)/(2)xx5xx((100)/(20))^(2)=62.50J`

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