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A coil resistance `20 Omega` and inductance `5 H` is connected with a `100 V` battery. Energy stored in the coil will be
A. 6.25 J
B. 62.5 J
C. 65.2 J
D. 26.5 J

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Best answer
Correct Answer - B
`I=(V)/(R)=(100)/(20)=5A`
`E=(1)/(2)LI^(2)=62.5J`

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