Question

If the binding energy per nucleon in `L i^7` and `He^4` nuclei are respectively `5.60 MeV` and `7.06 MeV`. Then energy of reaction `L i^7 + p rarr 2_2 He^4` is.
A. 19.6 MeV
B. 2.4 MeV
C. 8.4 MeV
D. 17.3 MeV

Answer 1

Correct Answer - D
(d) `B.E. of Li^7 = 39.20 MeV` and `He^4 = 28.24 MeV`
Hence binding energy of `2 He^4 = 56.48 MeV`
Energy of reaction `= 56.48 - 39.20 = 17.28 MeV`.