Question

A ray of light is incident at an angle of `45^(@)` on one face of a rectangular glass slab of thickness `10 cm` and refractive index `1.5`. Calculate the lateral shift produced.

Answer 1

Here, `i_(1) = 45^(@), t = 10 cm = 0.1 m`
`mu = 1.5`, lateral shift `= ?`
As `mu = (sin i_(1))/(sin r_(1))`
`:. sin r_(1) = (sin i_(1))/(mu) = (sin 45^(@))/(1.5) = (0.707)/(1.5) = 0.4713`
`r_(1) = sin^(-1) (0.4713) = 28.14^(@)`
lateral shift `= (t sin (i_(1) - r_(1)))/(cos r_(1))`
`= (0.1 sin (45^(@) - 28.14^(@)))/(cos 28.14^(@))`
`= (0.1 sin 16.86^(@))/(cos 28.14^(@)) = (0.1 xx 0.2900)/(0.8818) = 0.033 m`