Correct Answer - C
`P_(M) = P_(C_(5)H_(12))^(@).X_("L.P.of"C_(5)H_(12))+P_(C_(6)H_(14))^(@).X_("G.P.of"C_(6)H_(14))`
`= 440 xx (1)/(5) + 120 xx (4)/(5) = 184 mm`
Now `P_(C_(5)H_(12))^(@) . X_("L.P.of" C_(5)H_(12)) = P_(M) . X_("G.P.of"C_(6)H_(14))`
`440 xx (1)/(5) = 184 xx X_("G.P.of"C_(5)H_(12))`
`X_("G.P.of"C_(6)H_(12))=0.478`