Correct Answer - C
`P_(M)=P_(C_(5)H_(12))^@.X_(C_(5)H_(14))^@+P_(C_(6)H_(14))^@.X_(C_(5)H_(14))`
Thus `P_(M)=440xx(1)/(40)+120xx(4)/(5)=184` lt brgt Now, `P_(C_(5)H_(12))=P_(C_(5)H_(12))^0. X_(C_(5)H_(14)(l))=P_(M).X_(C_(5)H_(12)(g))`
`:.440xx(1)/(5)=184xxX_(C_(5)H_(12)(g))`
`:. X_(C_(5)H_(12)(g))= 0.478`