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If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal to
A. `+2 (d[A])/(d t)`
B. `-(1)/(3) (d[A])/(d t)`
C. `-(2)/(3) (d[A])/(d t)`
D. `-(3)/(2) (d[A])/(d t)`

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Correct Answer - C
`-(1)/(3)(d[A])/(d t) = (1)/(2)(d[B])/(d t) :. (d[B])/(d t) = -(2)/(3) (d[A])/(d t)`

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