Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
73 views
in Physics by (98.2k points)
closed by
A body of mass m is thrown at an angle to the horizontal with the initial velocity `v_0`. Assuming the air drag to be negligible, find:
(a) the momentum increment `Deltap` that the body acquires over the first t seconds of motion,
(b) the modulus of the momentum increment `Deltap` during the total time of motion.

1 Answer

0 votes
by (97.8k points)
selected by
 
Best answer
We have `Deltavecp=int vecFdt`
`=underset(0)overset(t)intmvecgdt=mvecg t` (1)
(b) Using the solution of problem 28(b), the total time of motion, `pi=-(2(vecv_0*vecg))/(g^2)`
Hence using `t=tau` in (1)
`|Deltavecp|=mg tau`
`=-2m(vecv_0*vecg)//g`(`vecv_0*vecg` is `-ve`)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...