Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
63 views
in Physics by (98.1k points)
closed by
A body of mass m is pushed with the initial velocity `v_0` up an inclined plane set at an angle `alpha` to the horizontal. The friction coefficient is equal to k. What distance will the body cover before it stops and what work do the friction forces perform over this distance?

1 Answer

0 votes
by (97.7k points)
selected by
 
Best answer
Let s be the sought distance, then from the equation of increment of M.E. `DeltaT+DeltaU=A_(f r)`
`(0-1/2mv_0^2)+(+mgssin alpha)=-kmg cos alphas`
or, `s=(v_0^2)/(2g)//(sin alpha+kcos alpha)`
Hence `A_(f r)=-kmgcos alphas=(-kmv_0^2)/(2(k+tan alpha))`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...