Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
261 views
in Physics by (84.7k points)
closed by
The value of sec`690^(@)` is :
A. `(sqrt(3))/(2)`
B. `-(sqrt(3))/(2)`
C. `(2)/(sqrt(3))`
D. `-(2)/(sqrt(3))`

1 Answer

0 votes
by (87.2k points)
selected by
 
Best answer
Correct Answer - C
The value ……….
`sec690^(@)= sec(720^(@)-30^(@))= sec(-30^(@))=sec30^(@) = (2)/(sqrt(3))`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...