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In an experiment with sonometer a tuning frok of frequency 256 Hz reaonates with a length of 25 cm and another tuning frok resonates with a length of 16 cm. Tension of the string remaining counstant the frequency to the second tuning fork is
A. 163.84 Hz
B. 400.Hz
C. 320 Hz
D. 204.8 Hz

1 Answer

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Best answer
Correct Answer - B
For sonometer, `nprop1/l`
`therefore(n_(1))/(n_(2))=(l_(2))/(l_(1)) rArr(256)/(n_(2))=n_(2)=(256xx25)/(16)=400 Hz`

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