Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
103 views
in Chemistry by (60.3k points)
closed by
The limiting molar conductivities `Lambda^@` for `NaCL, KBr` and `KCI` are ` 126, 152` and `150 S cm^2 ,ol^(-1)` respectively . The `Lambda^@` fro `NaBr S cm^2 "mol"^(-1)` is :
A. 302
B. 176
C. 278
D. 128

1 Answer

0 votes
by (66.4k points)
selected by
 
Best answer
Correct Answer - D
`Lambda_(NaBr)^(0)=Lambda_(NaCl)^(0)+Lambda_(KBr)^(0)-Lambda_(CKl)^(0)`
`=126+152-150=128Scm^(2)mol^(-1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...