Question

The limiting molar conductivities `Lambda^@` for `NaCL, KBr` and `KCI` are ` 126, 152` and `150 S cm^2 ,ol^(-1)` respectively . The `Lambda^@` fro `NaBr S cm^2 "mol"^(-1)` is :
A. `278 " S " cm^(2)mol^(-1)`
B. `176" S " cm^(2)mol^(-1)`
C. `128" S " cm^(2) mol^(-1)`
D. `302" S "cm^(2)mol^(-1)`

Answer 1

Correct Answer - C
(c ) `Lambda_(NaBr)^(@)=Lambda_(NaCl)^(@)+Lambda_(KBr^(-))^(@)-Lambda_(KCl)^(@)`
`=(126+152-150)=128" S " cm^(2)mol^(-1)`.