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The equivalent conductivity of a solution containing 2.45 g of `CuSO_(4)` per litre, is `91.0 Omega^(-1) cm^(2) eq^(-1)`. Its conductivity would be
A. `2.9xx10^(-3) Omega^(-1) cm^(-1)`
B. `1.9xx10^(-3) Omega^(-1) cm^(-1)`
C. `2.4xx10^(-3) Omega^(-1) cm^(-1)`
D. `3.6xx10^(-3) Omega^(-1) cm^(-1)`

1 Answer

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Best answer
Correct Answer - A
`K= Lambda_(eq)xxC=(91 Omega^(-1) cm^(2) eq^(-1)) (2.54/(159//2xx1000)eq)`
`=2.9xx10^(-3) Omega^(-1) cm^(-1)`

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