Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
205 views
in Chemistry by (60.3k points)
The equivalent conductivity of a solution containing 2.45 g of `CuSO_(4)` per litre, is `91.0 Omega^(-1) cm^(2) eq^(-1)`. Its conductivity would be
A. `1.45xx10^(-3)Omega^(-3)cm^(-1)`
B. `2.17xx10^(-3)Omega^(-3)cm^(-1)`
C. `2.90xx10^(-3)Omega^(-1)cm^(2)`
D. `2.9xx10^(-3)Omega^(-1)cm^(-1)`

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...