Question

For a transistor , `alpha_(dc)` and `beta_(dc)` are the current ratios, then the value of `(beta_(dc) - delta_(dc))/(alpha_(dc) . beta_(dc))`
A. 1
B. 1.5
C. 2
D. 2.5

Answer 1

Correct Answer - A
From the relation,
`beta_(dc) = (alpha_(dc))/(1-alpha_(dc))`
`rArr (1-alpha_(dc)) = (alpha_(dc))/(beta_(dc))`
Also, `(beta_(dc) - alpha_(dc))/(alpha_(dc).beta_(dc)) = (beta_(dc)(1-(alpha_(dc))/(beta_(dc))))/(alpha_(dc).beta_(dc))`
Using relation (i), we get
`= (1-(alpha_(dc))/(beta_(dc)))/(alpha_(dc) ) = (1-(1-alpha_(dc)))/(alpha_(dc))`
`= (1-1 + alpha_(dc))/(alpha_(dc)) = 1`