Question

For a transistor , `alpha_(dc)` and `beta_(dc)` are the current ratios, then the value of `(beta_(dc) - alpha_(dc))/(alpha_(dc) . beta_(dc))`
A. 1
B. 1.5
C. 2
D. 2.5

Answer 1

Correct Answer - A
`beta_(dc)=(alpha_(dc))/(1-alpha_(dc)) rArr (1-alpha_(dc))=(alpha_(dc))/(beta_(dc))`
`(beta_(dc)-alphadc)/(alpha_(dc).beta_(dc))=(beta_(dc)(1-(alpha_(dc))/(beta_(dc))))/(alpha_(dc).beta_(dc))`
`=(1-(alpha_(dc))/(beta_(dc))/(alpha_(dc))`
`=(1-1+alpha_(dc))/(alpha_(dc))=1`