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यदि `tan((pi)/(2)-(theta)/(2))=sqrt(3)` है तो का मान ज्ञात करे?

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`tan[(pi)/(2)-(theta)/(2)]=sqrt(3)`
`rArrtan[90-(theta)/(2)]=sqrt(3)`
`[pi=180^(@)]`
`rArr cot (theta)/(2)=30^(@)`
`rArr theta=60^(@)`
`rArrcos 60^(@)=(1)/(2)`

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