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Based on solute `-` solvent interactions, arrange the following in order of increasing solubility in `n-`octane and explain the result. Cyclohexane, `KCl,CH_(3)OH,CH_(3)CN`.

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(a) Cyclohexane and n-octane both are non-polar. They mix completely in all proportions.
(b) KCl is an ionic compound, KCl will not dissovle in n-octane.
(c ) `CH_(3)OH` is polar. `CH_(3)OH` will dissolve in n-octane.
(d) `CH_(3)CN` is polar but lesser than `CH_(3)OH`. Therefore, it will dissolve in n-octane but to a greater extent as compared to `CH_(3)OH`. Hence, the oreder is `KCl lt CH_(3)OH lt CH_(3)CN lt "Cyclohexane"`.

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