Question

A cylindrical ring is rolling without slipping. The ration of rotational and translational kinetic energies is
A. `0.25`
B. 0.5
C. 1
D. 1.5

Answer 1

Correct Answer - C
`KE_("translational")=(1)/(2)mv^(2)`
`KE_("rotational")=(1)/(2)l omega^(2)`
`=(1)/(2)(mr^(2))omega^(2)=(1)/(2)mv^(2)`
`(KE_("tans"))/(KE_("rot"))=1`.